30x^2+49x=0

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Solution for 30x^2+49x=0 equation: 



30x^2+49x=0

a = 30; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·30·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*30}=\frac{-98}{60}
=-1+19/30
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*30}=\frac{0}{60}
=0
$

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